Deleted member 18193
incel on incels.is
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- Joined
- Apr 23, 2019
- Posts
- 18,332
I have no idea what the question is even asking
You iqmog me if that helpsI'm too low iq
Yeah, yeah, yeah, yeah
I am a menace, keep me a rack just like tennis
I'm with the shit like I'm Dennis
I started this shit I'ma finish
Niggas be hatin', tryna blemish my image
Who want the smoke? .223 came with the scope
Extended clip long as a rope
We wipe his nose, just like he had him a cold
I knew that boy was a ho
Pull up with the gang, you know that we bangin'
What is your set, nigga? What is you claimin'?
I am a beast, you cannot tame it
Don't point the finger, this shit can get dangerous
These niggas hatin', these niggas plottin'
Ooh, he got money I'm runnin' his wallet
You say you a killer, lil' nigga stop it
In a shoot out your gun was droppin'
You really a fraud
XD
Who ?NLE Choppa... gay
Who ?
Whom ? XD
What ??? XDShotta Flow
What ??? XD
This is anti-nigger mathematics.what is this nigger shit
I'm close to 15k.You don’t need more posts
I'm close to 15k.
I'll be satisfied with 20k tbh or 25k.I want 30k
I'll be satisfied with 20k tbh or 25k.
Your mom.Lame its all or nothing
View attachment 232187
I have no idea what the question is even asking
what is this nigger shit
I see.Not one math
lmaothe answer is fish
The question is asking you to prove that all values of the function that you find in the 2nd quadrant map to the first.
Thank you. I'm not actually taking CA, just been trying to learn it on my own(turned out to be a bad idea) but I was curious to see if there were any mathcels here who have taken it. Its probably too advanced for me anyway atm so I'll just wait until I take it laterSo I just opened up wikipedia, and this came up:
Ifis an open subset of the complex plane, then a functionis conformal if and only if it is holomorphic and its derivative is everywhere non-zero on.
and
In mathematics, a holomorphic function is a complex-valued function of one or more complex variables that is, at every point of its domain, complex differentiable in a neighborhood of the point.
so basically, I think you need to prove that it has a a non zero derivative everywhere.
Thank you. I'm not actually taking CA, just been trying to learn it on my own(turned out to be a bad idea) but I was curious to see if there were any mathcels here who have taken it. Its probably too advanced for me anyway atm so I'll just wait until I take it later
I do have the solution, if anyone was interested:
View attachment 232270
Calculus I, II, III, Linear Algebra and Differrential Equations, which is the highest level math engineering students take in the program I'm in. I am becoming more interested in math and physics though. I know I won't get the depth of the material that I would If took one or any of those classes during a semester, but I do want to branch out my math skills a bit on my ownI admire your effort to self-study a very important subject that so many others dislike. You must know, however, that mathematics is a very deep subject where the fundamentals are paramount. Learning topics in math for which you may not have the necessary background is like building a house with random bricks and beams missing, where the foundation can cave in and collapse at any moment.
What's your background in math?
Calculus I, II, III, Linear Algebra and Differrential Equations, which is the highest level math engineering students take in the program I'm in. I am becoming more interested in math and physics though. I know I won't get the depth of the material that I would If took one or any of those classes during a semester, but I do want to branch out my math skills a bit on my own